IM FINALLY BLOGGING!

okay so sorry its taken so long. Anyways..

3/16

Mr. Dickie put multiple practice problems on the board that I payed very close attention to just for you guys (and my grade:/)

#1 the guy up there^ pulling the car (picture it with wheels). mass of car= 1.5kg; person pulling with a force of 10N. find acceleration.

a= Fun/mass SO a=10N/1.5kg and you get 6.67 m/s^2 as the acceleration

#2 okedoke so the picture with the finger pushing the block is next. needed the acceleration. Given: finger pushing with 10N; mass of block=1.5kg. oh and theres M (mew thing)=0.15

first we need to find friction. so we do Force of Friction= (Mlittlek)(Normal Force)

=(0.15)(15N) to get frictional force of 2.25 N

Next we need the acceleration so we take the Force of the pushing (10N) and subtract the force of friction (2.25) to get 7.75N. Then divide that by the mass (1.5kg) and we get 5.17m/s^2 as the acceleration.

#3 so there is a pulley system. the car on top is 1 kg and the weight pulling it is 0.2kg. to find the acceleration we take the Fun/mass.

a=2N/1.2kg equalssssss 1.67 m/s^2

#4 ELEVATOR PROBLEMMM

So Mr. Dickie, with a mass of 78kg is in an elevator that accelerates at 3m/s^2 when it starts moving up. **this time we are given the acceleration and want the Fun!

Fun= (a)(m)

Fun=(3m/s^2)(78kg) = 234N

You may think you are done but wait! you have to add 234 and 780 to get your grand total of 1014N as your normal force !

#5 Mr Dickie is in an elevator moving up at 2.7m/s^2. the elevator slows down and a rate of 3m/s^2. oh and he still has the same mass of 78kg.

So to do this problem we dont even need the 2.7 m/s/s part. ignore that. We just find the force unbalanced again which is still 234N and this time instead of adding that to 780 we SUBTRACT it from 780 to get 546 as the normal force

3/21

So we basically just worked on review sheet for our TEST ON THURSDAYY:O

that is all.